36-20x^2=0

Solution for 36-20x^2=0 equation:

36-20x^2=0

a = -20; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-20)·36
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{5}}{2*-20}=\frac{0-24\sqrt{5}}{-40}
=-\frac{24\sqrt{5}}{-40}
=-\frac{3\sqrt{5}}{-5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{5}}{2*-20}=\frac{0+24\sqrt{5}}{-40}
=\frac{24\sqrt{5}}{-40}
=\frac{3\sqrt{5}}{-5}
$